Table of Contents
We’re on
That’s a nice way to start, Jonny
Are you such a dreamer
To put the world to rights?
I’ll stay home forever
Where two and two always makes a five!
Who hasn’t heard this amazing number from Radio head? The makers of this song were quite sure that two and two make a five.When did this become a popular question? Well, the credit goes to the film
Two & Two (2011 film) which made it a popular debate.
However, when Iapplied the same logic in my Maths exam, as a kid, my professor marked itwrong. I felt deceived, to be honest. Ever since, I have always wished ofproving that grumpy professor wrong and I am glad I have finally found few wayout!
Has yourprofessor also forced you to believe that 2 + 2 = 4?
It’s time toprove him wrong!
After all you are a Small Einstein, who has the liberty to challenge even the axioms.
It’s finally that moment when you can proudlytell him how
2 + 2 = 5
Wondering how?Grab a bowl of nachos as you scroll through the top six ways to prove this seeminglyimpossible equation.
Method 1:
First, let us solve this strange problem with the simplest possible method.
Let us assume:
0 = 0
Now “0” can result from the subtraction of one number with itself. So, let us assume that the two figures at L.H.S. and R.H.S. are 4, and 10.
Such that…. 4 – 4 = 10 – 10
Where, 4 can be written as 2*2
And 10 can be written as 2*5
Solving the equation further we get,
=> 2²-2² = 2×5 – 2×5
=> (2 – 2)(2 + 2) = 5(2 – 2)
Cancelling (2–2) from both sides we get
=> 2 + 2 = 5 (Hence proved)
Think thismethod was too plain to convince your professor? Are you looking for something crisper?Don’t worry, have a look at the next method.
Well, its good to be achoosy friend who will not believe in anything that the other friend says.
So for those choosy friendsof ours, who are not satisfied with the above logic, we have a second answer.
Method 2:
Let’s now try tosolve this problem by using a different method. How about tossing in somefractions to make the struggle look more serious?
Let us assume:
-20 = -20———- (1)
Where 20 canalso be written as:
=> 16 – 36 and
=> 25 – 45
Now, placingthese values in equation (1) we get:
=> 16 – 36 = 25 – 45
Which can alsobe written as:
=> 42 – 4 x 9 + 81/4 = 52 – 5 x 9 + 81/4
=> 42 – (2 x 4 x 9/2) + (9/2)2 = 52 – (2 x 5 x 9/2) + (9/2)2
=> (4 – 9/2)2= (5 – 9/2)2
=> (4 – 9/2)= (5 – 9/2)
=> 4 = 5
Which eventuallyproves:
=> 2 + 2 = 5 (Hence Proved)
Well, even Pythagoras was condemned by
few, for saying that the earth is round. It is always good to refer to a new
method to prove yourself. So here goes method 3.
Challenging Mathematical Conventions: Two Equals Five
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Method 3:
Let us nowrelate this problem with a real-life example.
According to thegiven data:
2 + 2=5
Or
4 = 5
Let us supposeyou have 4 chocolates and you gave all of them to poor children. Now you have 0chocolates. When represented mathematically, you can write it as :
=> 4 – 4 = 0
Now, consideryour friend has 5 oranges, and he also gives all of them to those children. Healso ends up having nothing left with him. Mathematically:
=> 5 – 5 = 0
We can write
=> 0 = 0
=> 4 – 4 = 5 – 5
This can also bewritten as:
=> 4(1–1) =5(1–1)
=> 4=5((1–1)/(1–1))
=> 4 = 5
OR
=> 2 + 2 = 5
OR
=> 2+2=2+2+1
OR
=> 2+2+1=2+2
Though thismethod proves that 2 + 2 = 5 but it’s not one of my favorites. So, I thought ofadding some more spice to the problem. And when I say spice, I mean geometry.After all, things are always better understood pictorial representation, isn’tit?
Some people are not convinced by digits. So getconvinced in angles with Method 4
Method 4:
Any geometrylovers out there? Here’s the geometrical solution to prove our unusual problem.
Let us suppose,there’s a triangle with AB = 4, AC = 5 and BC = 3.
Construct theangle bisector of ∠A and the perpendicular bisector of segment B.C.
Now, in theconstructed figure:
AB = 4
AC = 5
So, the anglebisector and perpendicular bisector are not parallel. Hence, they intersect ata point O. Drop perpendiculars OR and OQ to sides A.B. and A.C., respectively.Form segments O.B. and O.C.
Case 1:
AO = AO byreflexivity,
∠RAO = ∠QAO (AO is an angle bisector)
∠ARO = ∠AQO (both are right angles)
By A.A.S. congruence, ΔARO ≅ ΔAQO.
Consequently byCPCTC, AR = AQ and RO = OQ. ——-(1)
Case 2:
OD = OD byreflexivity,
∠ODB = ∠ODC (both are right angles)
BD = DC (OD bisects BC)
By S.A.S.congruence, ΔODB ≅ ΔODC.
Therefore, byCPCTC, O.B. = O.C. ——-(2)
Since we haveproved that
R.O. = OQ———-(1)
OB = OC———-(2)
Also, since∠O.R.B. and ∠O.Q.C. are both right angles, the hypotenuse-leg theorem forcongruence implies ΔORB ≅ ΔOQC. Therefore, by CPCTC, B.R. = Q.C.—————(3)
We have shownthat AR = AQ and BR = QC. Therefore, AB = AR + RB = AQ + QC = AC.
In other words, 4 = 5,
Thus, 2 + 2 = 5.
What? Is it toocomplex to be understood? Well, I loved it because I love geometry. However, Istill have a surprise for those who didn’t like this method much. Wonderingwhat it may be? Read on.
So, that’s howyou prove 2 + 2 = 5. Wasn’t that easy?.
I bet your professor would give you anaccolade for proving him wrong! You are going to be his new favourite for sure!
Even if the solution may be wrongbut this high level of logic will surely take your professor or teachers aback.
Method 5 (A bit funny):
This was how one of our friends made the equation true. DONT try it.
In his words…
“There were 2 boys trying to snatch 2mangoes each from a friend of mine who had 5 mangoes.
I had been on bad terms with my friends.
I asked all three of them to fight overand whoever wins, would get the 4 mangoes.
My friend kept 5 mangoes on the groundand started fighting.
The three fought amongst themselves for quitelong.
I reported my teacher that they werefighting. My teacher made them kneel down in front of the class and I wasenjoying all the 5 mangoes.”
So I got 2 boys willing to get 2 mangoeseach from my friend to get me 5 mangoes in total.”
Well, you would think it is aprogramming joke till you go through it.
Method 6:
You are going tolove this last method, especially if you are a programming aficionado.
Yes! You cansolve this using a simple and easy code as well. All you have to do is, typethese few lines of code, compile it and see for yourself that 2+2=5.
$ cat test.c
#include<stdio.h>
int main() {
int a = 3;
int b = 3;
// aren’t wesupposed to add 2 and 2 ??/
a = 2;
b = 2;
printf(“%d\n”,a + b);
return 0;
}
$ gcc -W -Wall-trigraphs test2.c 2>/dev/null
$ ./a.out
5
So, that’s howyou prove 2 + 2 = 5. Wasn’t that easy? I bet your professor would give you anaccolade for proving him wrong! You are going to be his new favourite for sure!
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